# Line slope calculator x+7y=31

**Straight line given by points A[3; 4] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.1429x+4.4286

**Canonical form of the line equation:**x+7y-31 = 0

**Parametric form of the line equation:**

x = 7t+3

y = -t+4 ; t ∈ R

**Slope:**m = -0.1429

**Slope angle of line: φ =**-8°7'48″ = -0.1419 rad

**X intercept:**x

_{0}= 31

**Y intercept:**y

_{0}= q = 4.4286

**Distance line from the origin:**d

_{0}= 4.3841

**The length of the segment AB: |AB| =**7.0711

**Vector: AB =**(7; -1)

**Normal vector: n =**(1; 7)

**Midpoint of the segment AB: M =**[6.5; 3.5]

**Perpendicular Bisector equation:**7x-y-42 = 0

**Vector OA = (3; 4) ; |OA| = 5**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 36°25'51″ = 0.6358 rad**